(a) Substance X is sodium butanoate.
(b) Neutralization reaction
(c) methanoic acid (formic acid)
Explanation:
(a) We have the following chemical reaction:
CH₃-CH₂-CH₂-COOH (aq) + NaOH (aq) → CH₃-CH₂-CH₂-COO⁻Na⁺ (aq) + H₂O (l)
where:
(aq) - aqueous
(l) - liquid
X compound is sodium butanoate (CH₃-CH₂-CH₂-COO⁻Na⁺)
(b) In this reaction an acid react with a base to produce a salt and water, so this reaction will be called a neutralization reaction.
(c) methanoic acid (formic acid) will react with sodium hydroxide to produce sodium methanoate
HCOOH (aq) + NaOH (aq) → HCOONa (aq) + H₂O (l)
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neutralization reaction
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