Answer:
The required ratio is 2:1
Step-by-step explanation:
Consider the provided information.
The surface area of a six sides cube, is 6s²
It is given that the sides are 3 mm long.
Therefore, the surface area is:
[tex]6s^2=6(3)^2\\=6\times9\\=54[/tex]
Hence, the surface area is 54 mm²
The volume of cube is [tex]s^3[/tex]
Therefore, the volume is:
[tex]s^3=(3)^3\\=27[/tex]
We need to find the ratio of surface-area-to-volume
Therefore the required ratio is:
[tex]\frac{\text{Surface area}}{Volume} =\frac{54}{27}=\frac{2}{1}[/tex]
Hence, the required ratio is 2:1
