Answer:
3.53 m/s towards the left
Explanation:
[tex]m_1[/tex] = Mass of first glider = 400.5 g
[tex]m_2[/tex] = Mass of Second glider = 500 g
[tex]u_1[/tex] = Initial Velocity of first object = 2.3 m/s
[tex]u_2[/tex] = Initial Velocity of second object = -2.95 m/s
As momentum and Energy is conserved
[tex]m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}[/tex]
[tex]{\tfrac {1}{2}}m_{1}u_{1}^{2}+{\tfrac {1}{2}}m_{2}u_{2}^{2}={\tfrac {1}{2}}m_{1}v_{1}^{2}+{\tfrac {1}{2}}m_{2}v_{2}^{2}[/tex]
From the two equations we get
[tex]v_{1}=\frac{m_1-m_2}{m_1+m_2}u_{1}+\frac{2m_2}{m_1+m_2}u_2\\\Rightarrow v_1=\frac{0.4005-0.5}{0.4005+0.5}\times 2.3+\frac{2\times 0.5}{0.4005+0.5}\times -2.95\\\Rightarrow v_1=-3.53\ m/s[/tex]
The velocity of first glider after collision is 3.53 m/s towards the left
