Answer:
P = 80 KPa
Wt== 160. 84 KN
Explanation:
Given that
Depth ,h= 8 m
Diameter ,d= 1.6 m
g= 9.8 N/kg
We know that
Density of water ,ρ=1000 kg/m³
Pressure P
P = ρ g h
P =1000 x 10 x 8
P = 80 KPa
The force on the bottom F
F= P.A
A= π/4 d²
A= 0.785 x 1.6² m²
A= 2.01 m²
F= P.A
F= 80 x 2.01 KN
F= 160.84 KN
So the wight of the column = 160. 84 KN
This question involves the concepts of density, weight, and pressure of a column of a liquid.
a) The pressure at the bottom of the column is "78400 Pa".
b) The weight of this column of water is "157632.55 N".
a)
The pressure at the bottom of the water column is given as follows:
[tex]P=\rho gh[/tex]
where,
P = Pressure at the bottom = ?
[tex]\rho[/tex] = density of water = 1000 kg/m³
g = acceleration due to gravity = 9.8 m/s²
h = depth of water column = 8 m
Therefore,
[tex]P=(1000\ kg/m^3)(9.8\ m/s^2)(8\ m)[/tex]
P = 78400 Pa = 78.4 KPa
b)
Now, the weight of this column of water can be calculated as follows:
[tex]W = \rho Vg[/tex]
where,
W = Weight = ?
V = Volume = [tex]\pi \frac{d^2}{4}(h)=\pi \frac{(1.6\ m)^2}{4}(8\ m)[/tex] = 16.1 m³
Therefore,
[tex]W = (1000\ kg/m^3)(16.1\ m^3)(9.8\ m/s^2)[/tex]
W = 157632.55 N = 157.6 KN
Learn more about density here:
https://brainly.com/question/24386693?referrer=searchResults
The attached picture shows the concept of density.
