Answer:
[tex]F=8.22\times 10^{-9}\ N[/tex]
Explanation:
Given that,
Current in wire 1, [tex]I_1=1.6\ A[/tex]
Current in wire 2, [tex]I_2=3.6\ A[/tex]
Separation between wires, d = 1.4 m
Length of wire, l = 1 cm = 0.01 m
The force acting on wire 1 due to wire 2 is given by :
[tex]F=\dfrac{\mu_oI_1I_2l}{2\pi d}[/tex]
[tex]F=\dfrac{4\pi \times 10^{-7}\times 1.6\times 3.6\times 0.01}{2\pi \times 1.4}[/tex]
[tex]F=8.22\times 10^{-9}\ N[/tex]
So, the magnitude of force on wire 1 due to wire 2 is [tex]8.22\times 10^{-9}\ N[/tex]. Hence, this is the required solution.
