Assume that random guesses are made for seven multiple choice questions on an SAT​ test, so that there are nequals7 ​trials, each with probability of success​ (correct) given by pequals0.55. Find the indicated probability for the number of correct answers. Find the probability that the number x of correct answers is fewer than 4.

Respuesta :

Answer: 0.5438

Step-by-step explanation:

Given : Sample size : n=7

Probability of success​ : p=0.55

Using Normal approximation for binomial distribution , we have

[tex]\mu= np =7(0.55)=3.85[/tex]

[tex]\sigma=\sqrt{np(1-p)}=\sqrt{7(0.55)(0.45)}=1.32[/tex]

The probability that the number x of correct answers is fewer than 4 is given by :-

[tex]P(x<4)=P(z<\dfrac{4-3.85}{1.32})\\\\=P(z<0.11)=0.5438[/tex]

Hence, the probability that the number x of correct answers is fewer than 4= 0.5438