Respuesta :
Answer:
The phenotypic and genotypic ratios for each generation are determined below.
Explanation:
As we assume P1 individuals are homozygous (i.e EE, VV, ee, vv)
P1 Generation:
gray long winged X ebony vestigial winged
EEVV X eevv
Gametes:
E V X e v
F1 Geneation:
EeVv ---------------> All heterozygous gray long winged .
Ratio for genotype:
100% heterozygous gray long winged
For F2 Generation:
F1 x F1
EeVv X EeVv
Punnett Square for dihybrid cross:
EV Ev eV ev
--------------------------------------------------------------
EV EEVV EEVv EeVV EeVv
Ev EEVv EEvv EeVv Eevv
eV EeVV EeVv eeVV eeVv
ev EeVv Eevv eeVv eevv
RATIO OF PHENOTYPE:
Gray long winged : Gray short winged : Ebony long winged : Ebony short winged
9 : 3 : 3 : 1
RATIO OF GENOTYPE:
EEVV : EEVv : EeVV : EeVv : EEvv : Eevv : eeVV : eeVv : eevv
1 : 2 : 1 : 2 : 4 : 2 : 1 : 2 : 1
Dominant and the recessive are the two forms of the alleles of the genes. The ratio of the F2 cross in Drosophila will be 9:3:3:1.
What is heterozygous and purebred?
Heterozygous is the pair of the trait in a recessive and dominant form while the purebred is the condition that has the same pair of dominant or recessive alleles.
The dominant alleles are grey (E) and have long wings (V) while the recessive is of the ebony (e) color and vestigial wings (v).
The parent is purebred (P1) = EEVV and eevv
See the attached image below for the cross.
The phenotypic ratio of the cross can be given as:
Gray long-winged : Gray short-winged : Ebony long-winged : Ebony short-winged = 9:3:3:1
The genotypic ratio of the cross can be given as:
EEVV : EEVv : EeVV : EeVv : EEvv : Eevv : eeVV : eeVv : eevv = 1 : 2 : 1 : 2 : 4 : 2 : 1 : 2 : 1
Therefore, the genotypic ratio of the F1 will be 100% heterozygous gray long-winged and 9:3:3:1 is the phenotypic ratio of the F2 generation.
Learn more about dihybrid cross here:
https://brainly.com/question/15588257
