Answer:
[tex]\sqrt{118}\approx 10.86[/tex]
[tex]\sqrt{319}\approx 17.86[/tex]
Step-by-step explanation:
Consider the provided number.
We need to find the approximate value of [tex]\sqrt{118}[/tex] to the nearest hundredth.
First find two perfect squares that the irrational number falls between.
[tex]100<118<121[/tex]
118 is lying between 100 and 121, therefore the square root value of 118 will be somewhere between 10 and 11.
[tex]\sqrt{100}<\sqrt{118}<\sqrt{121}[/tex]
[tex]10<\sqrt{118}<11[/tex]
118 is closer to 121 as compare to 100.
Therefore, [tex]\sqrt{118}\approx 10.86[/tex]
Consider the number [tex]\sqrt{319}[/tex]
First find two perfect squares that the irrational number falls between.
[tex]289<319<324[/tex]
319 is lying between 289 and 324, therefore the square root value of 319 will be somewhere between 17 and 18.
[tex]\sqrt{289}<\sqrt{319}<\sqrt{324}[/tex]
[tex]17<\sqrt{319}<18[/tex]
319 is closer to 324 as compare to 289.
Therefore, [tex]\sqrt{319}\approx 17.86[/tex]