An electric generator contains a coil of 140 turns of wire, each forming a rectangular loop 71.2 cm by 22.6 cm. The coil is placed entirely in a uniform magnetic field with magnitude B = 4.32 T and initially perpendicular to the coil's plane. What is in volts the maximum value of the emf produced when the loop is spun at 1120 rev/min about an axis perpendicular to the magnetic field?

Respuesta :

Answer:

11405Volt

Explanation:

To solve this problem it is necessary to use the concept related to induced voltage or electromotive force measured in volts. Through this force it is possible to maintain a potential difference between two points in an open circuit or to produce an electric current in a closed circuit.

The equation that allows the calculation of this voltage is given by,

[tex]\epsilon = BAN \omega[/tex]

Where

B = Magnetic field

A= Area

N = Number of loops

[tex]\omega[/tex]= Angular velocity

Our values previously given are:

[tex]N = 140[/tex]

[tex]A = 71.2*10^{-2}m*22.6*10^{-2}m=0.1609m^2[/tex]

[tex]B = 4.32 T[/tex]

[tex]\omega = 1120 rev / min[/tex]

We need convert the angular velocity to international system, then

[tex]\omega = 1120 rev/min[/tex]

[tex]\omega = 1120rev/min*\frac{2\pi}{1rev}*\frac{1min}{60sec}[/tex]

[tex]\omega = 117.2rad/s[/tex]

Applying the equation for emf, we replace the values and we will obtain the value.

[tex]\epsilon = BAN \omega[/tex]

[tex]\epsilon = (4.32)(0.1609)(140)*117.2[/tex]

[tex]\epsilon = 11405Volt[/tex]