Answer:
Price of each senior citizen ticket is [tex]\$12[/tex] and one child ticket is[tex]\$3[/tex]
Step-by-step explanation:
Let the price of each senior citizen ticket be x.
Let the price of each Child ticket be y.
Tickets sold on first day which are given as,
5 senior citizen tickets and 14 child tickets for a total of $102.
[tex]5x+14y = \$ 102 \ \ equation \ 1[/tex]
Tickets sold on first day which are given as,
$153 on the second day by selling 11 senior citizen tickets and 7 child tickets.
[tex]11x+7y= \$153 \ \ \ equation\ 2[/tex]
Now multiplying by 2 equation 2 we get
[tex]2\times (11x+7y)= 2 \times\$153\\22x+14y = \$ 306 \ \ \ equation\ 3[/tex]
Now Subtracting equation 1 from equation 3 we get
[tex]17x= 204\\x=\frac{204}{17} = \$12[/tex]
Substituting value of x in equation 1 we get
[tex]5 \times12+14y=\$102\\14y=\$102-42\\14y= \$42\\y=\$\frac{42}{14}=\$4[/tex]
Hence Senior Citizen ticket price is [tex]\$12[/tex] and Child ticket price is [tex]\$3[/tex]
