Answer:
[tex]I = \dfrac{5 ML^2}{12}[/tex]
Explanation:
given,
mass of metallic sheet = M
shape of the sheet is square of length L
Moment of inertia When passing through center
= [tex]\dfrac{ML^2}{6}[/tex]
now, calculating Moment of inertia from one corner
I = Iₓ + MR²
R is the distance is L/2
[tex]I = \dfrac{ML^2}{6} + \dfrac{ML^2}{4}[/tex]
[tex]I = \dfrac{2ML^2 + 3 ML^2}{12}[/tex]
[tex]I = \dfrac{5 ML^2}{12}[/tex]
Moment of inertia through one corner [tex]I = \dfrac{5 ML^2}{12}[/tex]
