Many professional singers have a range of 2.5 octaves or greater. Suppose a soprano's range (1 point) extends from A below middle C (frequency 220 Hz) up to Eb above high C (frequency 1244 Hz). The vocal tract can be modeled as a resonating air column that is open at the top and closed at the bottom; the column extends from the mouth down to the diaphragm in the chest cavity. You can assume that the lowest note is the fundamental. How long is this column of air ifv 344 m/s?
A. 45.6 cm
B. 51.1 cm
C. 24.7 cm
D. 39.1 cm

Respuesta :

This column of air ifv 344 m/s is D. 39.1 cm

Explanation:

Many professional singers have a range of 2.5 octaves or greater. Suppose a soprano's range (1 point) extends from A below middle C (frequency 220 Hz) up to Eb above high C (frequency 1244 Hz). The vocal tract can be modeled as a resonating air column that is open at the top and closed at the bottom; the column extends from the mouth down to the diaphragm in the chest cavity. You can assume that the lowest note is the fundamental. How long is this column of air ifv 344 m/s?

Organ pipes are musical instruments  used to produce musical sound by blowing air into the pipe. Organ pipes are have two types (a) closed organ pipes, closed at one end (b) open organ pipe, open at both ends. An open organ pipe has two adjacent natural frequencies of 500 and 600 Hz.

If we draw the open pipe as the opera song start to singing. Therefore the lower frequency is 220 Hz. To find the lower length we should use lower frequency and velocity as follows:

[tex]f = \frac{v}{4L} \\L = \frac{v}{4f} \\L = \frac{344}{4*220} \\L = 0.3909 m\\L = 39.1 cm[/tex]

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