The equation of circle with center at origin and passing through the point (-3,-1) is:
[tex]x^2+y^2=10[/tex]
Step-by-step explanation:
The general form of equation of circle is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
If the center is at origin, then the equation will be:
[tex]x^2+y^2=r^2[/tex]
Given point is: (-3,-1)
The distance of the point from origin will be the radius
The distance of any point from the origin is given by:
[tex]r=\sqrt{x^2+y^2}\\Putting\ the\ given\ point\\r=\sqrt{(-3)^2+(-1)^2}\\r=\sqrt{9+1}\\r=\sqrt{10}[/tex]
Putting the value of r in standard equation
[tex]x^2+y^2=(\sqrt{10})^2\\x^2+x^2=10[/tex]
The equation of circle with center at origin and passing through the point (-3,-1) is:
[tex]x^2+y^2=10[/tex]
Keywords: Equation of circle, Radius
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