contestada

Jonathan throws an apple straight up (in a positive direction), reaching a maximum height of 30 meters. Neglecting air resistance, what is the ball's velocity just when it leaves Jonathan's hand?

Respuesta :

The initial velocity of the apple is 24.2 m/s

Explanation:

The motion of the apple is a free fall motion (acted upon the force of gravity only), so it is a motion at constant acceleration. We can find the initial velocity by using the following suvat equation:

[tex]v^2-u^2=2as[/tex]

where:

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

In this problem we have:

v = 0 is the final velocity (at the maximum height, the velocity is zero)

s = 30 m is the vertical displacement

[tex]a=g=-9.8 m/s^2[/tex] is the acceleration of gravity (negative since it is downward)

Substituting and solving for u, we find the initial velocity:

[tex]u=\sqrt{-2as}=\sqrt{-2(-9.8)(30)}=24.2 m/s[/tex]

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