Prelaboratory Assignment 11
25 pts
Name
1. Consider the reaction
2 KMnO4 + 10 KS.Oz + 16 HCl → 2 MnCl2 + 5 K2S40671
03 + 16 HCl → 2 MnCl2 + 5 KS406 + 12 KCl + 8 H2O
a) What is the oxidation number of
8 pts
i. Mn in MnCl2
ii. Mn in Mn04
iii. S in K2S406
iv. Cl in HCl

Respuesta :

I. Mn have a +2 oxidation number in MnCl₂

II. Mn have a +7 oxidation number in in KMnO₄

III. S have 0 and +2 oxidation numbers in K₂S₄O₆

IV. Cl have a -1 oxidation number in HCl

Explanation:

i. Mn have a +2 oxidation number in MnCl₂

Cl have a -1 oxidation number so in order to make the compound neutral the Mn need to have a +2 oxidation number.

II. Mn have a +7 oxidation number in in KMnO₄

O have a -2 oxidation number and K have +1 oxidation number so in order to make the compound neutral the Mn need to have a +7 oxidation number.

III. S have 0 and +2 oxidation numbers in K₂S₄O₆

O have a -2 oxidation number and K have +1 oxidation number. However this is more complicated to asses the oxidation number. Taking in account the chemical structure of  K₂S₄O₆, two S atoms will have a 0 oxidation number and the other two S atoms will have a +4 oxidation number.

IV. Cl have a -1 oxidation number in HCl

H have a +1 oxidation number so in order to make the compound neutral the Cl need to have a -1 oxidation number.

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oxidation numbers

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