From the given options 64 units is the area of square that Margo used. So, option D is correct.
SOLUTION:
Given, Margo draws a triangle. The lengths of the sides of the triangle are [tex]8^{\prime \prime}, 15^{\prime \prime} \text { and } 17^{\prime \prime}[/tex]
Margo uses the area of 3 squares to show that the triangle is a right triangle. We have to find the area, in square units, of a square that Margo uses . Now, we know that, we can prove a triangle as right angled triangle using Pythagoras theorem
[tex]\text { Pythagoras theorem } \rightarrow \text { hypotenuse }^{2}=\text { side }^{2}+\text { side }^{2}[/tex]
Assume that above theorem is equation of area of one square = sum area of two squares. Then, using area of three squares we can prove that a triangle is a right angle triangle.
Now, areas of the three squares will be [tex]8^{2}, 15^{2}, 17^{2} \rightarrow 64,225,289[/tex]
