Two long parallel wires carry currents of 1.77 A and 8.93 A . The magnitude of the force per unit length acting on each wire is 5.93×10−5 N/m . Find the separation distance of the wires expressed in millimeters.

Respuesta :

Answer:

533mm

Explanation:

The concept that we need to apply here to find the radius is the Force in a Magnetic Field,

That is basically Force per unit length in terms of the current, which is given by,

[tex]F= \frac{\mu_0I_1I_2}{2\pi R}[/tex]

Where,

[tex]\mu_0[/tex] is the permeability constant

[tex]I_i[/tex] is the current

R the radius

Re-arrange for Radius,

[tex]R = \frac{\mu_0 I_1I_2}{2\pi R}[/tex]

Replacing our values

[tex]R = \frac{4\pi*10^{-7}(1.77)(8.93)}{5.93*10^{-5}2\pi}[/tex]

[tex]R = 0.0533m[/tex]

Therefore the separation distance of the wires is 533mm