The acceleration of the car in section C is -3 m/s/s
Explanation:
The acceleration of a body is defined as:
[tex]a=\frac{\Delta v}{\Delta t}[/tex]
where
[tex]\Delta v[/tex] is the change in velocity of the body
[tex]\Delta t[/tex] is the time it takes for the body to change its velocity by [tex]\Delta v[/tex]
We notice that in a graph of velocity vs time, the slope of the graph is
[tex]m=\frac{\Delta v}{\Delta t}[/tex]
So we see that the slope of the graph corresponds to the acceleration of the object.
In section C of this graph, we have:
[tex]\Delta v = v-u=6 m/s - 12 m/s = -6 m/s[/tex] is the change in velocity of the object
[tex]\Delta t = 11 s - 9 s = 2 s[/tex] is the time interval
Therefore, the slope of the graph (and so, the acceleration of the car) in section C is:
[tex]a=\frac{-6}{2}=-3 m/s^2[/tex]
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