Answer:
Distance between the anchor points = 236 ft
Step-by-step explanation:
In the figure attached we will apply sine rule first to get the measure of AC.
sin60° = [tex]\frac{AC}{AB}[/tex]
0.866 = [tex]\frac{AC}{165}[/tex]
AC = 165 × 0.866
= 142.89 ft
Now we will apply Pythagoras theorem in the triangle ACD.
AD² = AC² + CD²
(210)² = (142.89)² + CD²
CD² = 44100 - 20418.75
CD = √(23681.25)
= 153.88 ft
Cos60° = [tex]\frac{BC}{AB}[/tex]
0.5 = [tex]\frac{BC}{165}[/tex]
BC = 165 × 0.5 = 82.5 ft
Distance between two anchor points = BC + CD
= 82.5 + 153.88
= 236.38
≈ 236 ft
Therefore, distance between the anchor points is 236 ft.
