Respuesta :
Answer:
The answer to your question is: 0.118 moles of water
Explanation:
Data
moles of water = ?
Vol of O2= 1.6
Temp = 324°K
Pressure = 0.984 atm
R = 0.082 atm l / mol°K
Process
1.- Calculate the moles of O₂ using the ideal gas formula.
PV = nRT
[tex]n = \frac{PV}{RT}[/tex]
[tex]n = \frac{(1.6)(0.984)}{(0.082)(324)}[/tex]
[tex]n = \frac{1.5744}{26.568}[/tex]
n = 0.059 moles of oxygen
2.- Find the moles of water
2 moles of water ------------------ 1 mol of oxygen
x ------------------ 0.059 moles
x = (0.059 x 2) / 1
x = 0.118 moles of water
The number of moles of H2O required to form 1.6 L of O2 at a temperature of 324 K and a pressure of 0.984atm is 0.118moles
- To calculate the number of moles of oxygen involved in the reaction can be calculated using the following expression:
PV = nRT
Where;
- P = pressure (atm)
- V = volume (L)
- n = number of moles (mol)
- R = gas law constant (0.0821 Latm/molK)
- T = temperature (K)
- n = (0.984 × 1.6) ÷ (0.0821 × 324)
- n = 1.5744 ÷ 26.6
- n = 0.059mol of O2.
- According to this reaction; 2H2O(l) → 2H2(g) + O2(g)
- 2 moles of H2O produce 1 mole of O2
- 0.059 moles of O2 will be produced when 0.059 × 2 = 0.118moles of H2O.
- Therefore, the number of moles of H2O required to form 1.6 L of O2 at a temperature of 324K and a pressure of 0.984atm is 0.118moles.
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