Answer:
CaCl₂
Explanation:
Given data:
Mass of calcium = 3.609 g
Mass of chlorine = 6.384 g
Empirical formula = ?
Solution:
Number of moles of calcium:
Number of moles of calcium = mass/ molar mass
Number of moles of calcium = 3.609 g/ 40 g/mol
Number of moles of calcium = 0.090 mol
Number of moles of chlorine:
Number of moles of chlorine = mass/ molar mass
Number of moles of chlorine = 6.384 g/ 35.5 g/mol
Number of moles of chlorine = 0.18 mol
Ca : Cl
0.090/0.090 : 0.18/ 0.090
1 : 2
Empirical formula:
CaCl₂
