Answer:
C. The program compiles despite the semicolon (;) on the for loop line, and displays 14.
Explanation:
For better representation, the for loop line of the code could also be written as follows:
for( i = 0; i < 10; i++) {
}
System.out.println(i+4);
This means that the for loop will run 10 times and at end of every cycle, the value of i will get incremented by 1. Therefore, at the end of the loop, the value of i = 10.
Note: You would almost think that the value of i at the end of the loop will be 9. But then, don't forget that the value of i gets incremented at the end of each cycle by 1. So at the end of the last cycle of the loop, i will have a value of 10. This is the reason why the loop ends in the first place knowing that the value of i is already 10 which makes the conditional statement of the for loop, (i<10), false.
Continuing, since the value of i at the end of the loop is now 10, the last statement in the code which is as follows:
System.out.println(i+4);
adds 4 to the value of i which gives 14.
Therefore, the console will display a value of 14.
Hope this helps!
