The final speed of the object is 15.3 m/s
Explanation:
The object in the problem is moving by uniformly accelerated motion (it is in free fall), so we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
[tex]a=g=9.8 m/s^2[/tex] is the acceleration of gravity (taking downward as positive direction)
s is the vertical displacement
For the object in this problem:
u = 0 (it starts from rest)
s = 12 m is the displacement of the object
Solving for v,
[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(12)}=15.3 m/s[/tex]
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