Answer:
s = 1.925 meters
Explanation:
Given that,
Horizontal force acting on the cart, F = 11 N
Mass of the cart, m = 35 kg
To find,
Distance covered by the cart in 3.5 seconds if it starts from rest.
Solution,
As the cart is starting from rest, u = 0
Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
Since, [tex]a=\dfrac{F}{m}[/tex]
[tex]s=\dfrac{1}{2}\times \dfrac{F}{m}\times t^2[/tex]
[tex]s=\dfrac{1}{2}\times \dfrac{11}{35}\times (3.5)^2[/tex]
s = 1.925 meters
Therefore, the distance covered by the cart is 1.925 meters.
