Answer:
[tex]\frac{x^{2} -\sqrt[3]{y}}{x+y}=9[/tex]
Step-by-step explanation:
we know that
The quotient means, divide the numerator by the denominator
In this problem
1) The numerator is "the square of a number minus the cubed root of another number"
Let
x ----> a number
y ----> another number
The algebraic expression of the numerator of the quotient is
[tex]x^{2} -\sqrt[3]{y}[/tex]
2) The denominator is "the sum of those two numbers"
so
The algebraic expression of the denominator of the quotient is
[tex]x+y[/tex]
3) The quotient of the square of a number minus the cubed root of another number and the sum of those two numbers is nine
Equate the quotient to the number 9
so
we have
[tex]\frac{x^{2} -\sqrt[3]{y}}{x+y}=9[/tex]
