Respuesta :
Answer:
1.0193
Explanation:
The concepts that we apply here is Frictional Force with a Force on the object with a angle.
We know that Frictional Force is equal to
[tex]F_f = \mu N[/tex]
The force acts downward because the moving is upward, then from the image that I attached, the forve is equal to,
[tex]Fcos30° = 3N(cos30) = 2.6[/tex]
In Y we have then
[tex]1.7N + f_x = 2.6[/tex]
[tex]f_x = 1.529N[/tex]
For the horizontal componentes we have that
[tex]N = (3N)sin30\°[/tex]
[tex]N = 1.5 N[/tex]
Using the first equation we have that
[tex]F_f = \mu N[/tex]
[tex]1.529N = \mu 1.5 N[/tex]
Re-arrange for [tex]\mu[/tex]
[tex]\mu = 1.0193[/tex]

The friction force is equal to the product of the coefficient of friction and normal force. Then the coefficient of kinetic friction between the wall and the block is 0.6.
What is the coefficient of friction?
It represents the surface roughness between the two bodies. If the value of this coefficient is more means more roughness hence more friction force and vice versa.
Before hanging new William Morris wallpaper in her bedroom, Brenda sanded the walls lightly to smooth out some irregularities on the surface.
The sanding block weighs 1.70 N and Brenda pushes on it with a force of 3.00 N at an angle of 30.0° with respect to the vertical, and angled toward the wall.
Force balance in the x-direction, we have
Normal force (N) = 3 × sin 30° = 1.5
Force balance in the y-direction, we have
[tex]\rm 3*cos 30^o = 1.7 + friction \ force \ (f_k) \\\\f_k = 0.90[/tex]
We know the friction force will be
[tex]\rm f_k = \mu* N\\\\0.9 = 1.5 \mu\\\\\mu = 0.6[/tex]
Then the coefficient of kinetic friction between the wall and the block is 0.6.
More about the coefficient of friction link is given below.
https://brainly.com/question/11808898