Which of the following equations defines a line that is parallel to the line y=-4/3x-4 and passes through the point (3,-1)
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Answer:
d
Step-by-step explanation:
given that your slop is -4/3, plug the (x,y) point in to the equation of y = -4x/3 +b
-1 = -4 + b , b = 3
y = -4x/3 + 3
Answer:
Step-by-step explanation:
The given line is
[tex]y=-\frac{4}{3}x-4[/tex]
Now, if the new line is parallel to the given one, that means it must have the same slope.
[tex]m=-\frac{4}{3}[/tex]
We also know that the new line passes through point (3,-1).
Then, we use the point-slope formula to find the equation of the new line:
[tex]y-y_{1} =m(x-x_{1} )\\y-(-1)=-\frac{4}{3}(x-3)\\ y=-\frac{4}{3}x+4-1\\ y=-\frac{4}{3}x+3[/tex]
Therefore, the line that passes through (3,-1) and it's parallel to the given line is: [tex]y=-\frac{4}{3}x+3[/tex].
The image attached show these parallel lines.