Answer:
A rectangle has a length 6m less than twice its width. when 5 m are added to the width, the resulting figure is a square with an area of 256m^2. find the distance of the original rectangle
width:: x
length:: 2x-6
-------
New width:: x+5
---
Equation:
(x+5)^2 =256 =16
16 is the original length
The dimensions of the original rectangle are 16 m and 11 m if the rectangle has a length of 6 m less than twice its width.
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
We have:
A rectangle has a length of 6 m less than twice its width.
Let width be x:
The length = 2x-6
New width = x+5
(x+5)² = 256
x = 11
The length = 2x - 6 = 2(11) - 6 = 16 m
Thus, the dimensions of the original rectangle are 16 m and 11 m if the rectangle has a length of 6 m less than twice its width.
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