Respuesta :
Answer:
Theoretical yield for Si = 2586.55*28.09= 72.7 Kg
Percentage yield is =2356.71/2586.55=91.11%
Explanation:
So the chemical equation for this reaction would be SiO2 + 2C = Si + CO
so n(SiO2)=m(SiO2)/M(SiO2)=155400/60.08=2586.55 mol
n(C)=m(C)/M(C)=77400/12.01=6444.63 mol
So Carbon is in exes.
n(Si)=m(Si)/M(Si)=66200/28.09= 2356.71 mol
Theoretical yield for Si = 2586.55*28.09= 72.7 Kg
Percentage yield is =2356.71/2586.55=91.11%
Answer:
theoretical yield: 72.50 kgSi
percent yield: 91.3%
Explanation:
The theoretical yield is limited by the initial mass of the limiting reactant, SiO2. The mass of Si can be calculated using stoichiometry as follows:
155.1 kgSiO2 ×1 kmol SiO2/ 60.085 kg SiO2 ×1 kmol Si/ 1kmol SiO2 ×28.085kg Si 1kmolSi= 72.50kg Si
Percent yield is a comparison of the theoretical yield to the actual yield. The mass of Si actually produced is given as 66.2 kg . Dividing this by the theoretical yield (72.50 kg ) and multiplying by 100 % gives you the percent yield.