Answer:
the distance is -6
Step-by-step explanation:
a to 0,0 is 1
b to 0,0 is 7
1-7= -6
The distance between point A (-1, 3) and point B (-7, 3) is 6 units
Solution:
Given, two points are A(-1, 3) and (-7, 3)
We need to find the distance between above two points.
We know that distance between two points [tex]P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right)[/tex] is given as:
[tex]d(P, Q)=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}[/tex]
[tex]\text { here, } x_{1}=-1, y_{1}=3, x_{2}=-7 \text { and } y_{2}=3[/tex]
Substitute the values we get,
[tex]\begin{array}{l}{\text { Distance }=\sqrt{((-7)-(-1))^{2}+(3-3)^{2}}} \\\\ {=\sqrt{(1-7)^{2}+(0)^{2}}=\sqrt{(-6)^{2}+0}} \\\\ {=\sqrt{36}=6}\end{array}[/tex]
Hence, the distance between two points is 6 units.
