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A 600-g block is dropped onto a relaxed vertical spring that has a spring constant k =190.0 N/m. The block becomes attached to the spring and compresses the spring 37.5 cm before momentarily stopping. While the spring is being compressed, what work is done on the block by the gravitational force on it?

Respuesta :

Answer:

Work done will be 2.205 j

Explanation:

We have given that the spring is compressed b 37.5 cm

So d = 0.375 m

Mass of the block m = 600 gram = 0.6 kg

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

Gravitational force on the block [tex]F=mg=0.6\times 9.8=5.88N[/tex]

Now we know that work done is give by [tex]W=Fd=5.88\times 0.375=2.205J[/tex]

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