Answer:
The required probability is 0.0281
Step-by-step explanation:
Consider the provided information.
Air-USA has a policy of booking as many as 18 persons on an airplane that can seat only 17.
Studies have revealed that only 82% of the booked passengers actually arrive for the flight.
Therefore, the probability of a person arrive is 0.82
Find the probability that t if Air-USA books 18 persons, not enough seats will be available.
Probability that 18 persons arrive = [tex](0.82)^{18}=0.0281[/tex]
Hence, the required probability is 0.0281