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2Al(s) + Fe2O3(s) → Al2O3(s) + 2Fe(s) T
he ΔHf for Fe2O3(s) = -824.3 kJ/mole.
The ΔHf for Al2O3(s) = -1675.7 kJ/mole.
Finish the equation.
ΔHrxn = [(1) ______ ( kJ/mole) + (2) ______ ( kJ/mole)] - [(1) ______ ( kJ/mole) + (2) ______ ( kJ/mole)]

Respuesta :

baraltoa

Answer:

ΔHrxn = [(1) -1675.5 ( kJ/mole) + (2) 0 ( kJ/mole)] - [(1) -824.3 ( kJ/mole) + (2) 0 ( kJ/mole)]

Explanation:

ΔHrxn = 2ΔHf (Al₂O₃)  - ΔHf (Fe₂O₃)

Remember that for pure elements in their standard state of temperature and pressure by definition their standard heats of formation are zero.

ΔHrxn = 2(-1675.7) - (-824.3) kJ/mol

ΔHrxn = 2527 kJ/mol

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