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What is the molarity of ZnCl2 that forms when 25.0 g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 275 mL. Tro, Nivaldo J.. Chemistry (p. 204). Pearson Education. Kindle Edition.

Respuesta :

Answer:

The molarity of ZnCl2 is 1.39 M

Explanation:

Step 1: The balanced equation

Z n ( s ) +  C u C l 2 ( a q )  →  Z n C l 2  ( a q )  +  C u ( s )

Step 2: Given data

The mass of zinc = 25.0 g

The volume of solution = 275 mL

Step 3: Calculate moles of Zinc

Moles of Zn = mass of Zn / Molar mass of Zn

Moles of Zn = 25.0 grams / 65.38 Molar mass

Moles of Zn = 0.382 moles

Step 4: Calculate moles of ZnCl2

For 1 mole of Zn consumed, we need 1 mole of ZnCl2

For 0.382 moles of Zn we produce 0.382 moles of ZnCl2

Step 5: Calculate the molarity of ZnCl2

Molarity = Moles / Volume

Molarity = 0.382 moles / 0.275 L

Molarity = 1.39 M

The molarity of ZnCl2 is 1.39 M

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