Respuesta :
Explanation:
Efficiency = work out / work in
e = mgh / Fd
e = (20 kg × 9.8 m/s² × 1 m) / (80 N × √(1² + 3²) m)
e ≈ 0.77
Round as needed.
Answer:
81.67%
Explanation:
Efficiency of the ramp [tex]E= \frac{W_o}{W_i}[/tex]
Work Input [tex]W_i[/tex]= F x s = 80 N x 3 m = 240 J
(F is the force applied and s is the distance moved)
Work Output = m g h (how much the box is lifted above the ground)
m is the mass, g is the acceleration due to gravity and h is the height.
[tex]W_o[/tex]= (20 kg)(9.8 m/s²)(1 m) = 196 J
Therefore, efficiency of the ramp is:
[tex]E= \frac{196J}{240J}= 0.8167[/tex]
In percentage, the ramp is 81.67% efficient.