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An open train car, with a mass of 2010 kg, coasts along a horizontal track at the speed 2.53 m/s. The car passes under a loading chute and, as it does so, gravel falls vertically into it for 3.25 s at the rate of 423 kg/s. What is the car's speed ????f after the loading is completed? Ignore rolling friction.

Respuesta :

Answer:

v' = 1.5 m/s

Explanation:

Given that,

Mass of the car, m = 2010 kg

Speed of the car, v = 2.53 m/s

The car passes under a loading chute and gravel falls vertically into it for 3.25 s at the rate of 423 kg/s. Mass loaded during this time, m' = 1374.75 kg

Let v' is the speed of car after the loading is completed. Using the conservation of momentum to find it.

[tex]mv=(m+m')v'[/tex]

[tex]v'=\dfrac{mv}{m+m'}[/tex]

[tex]v'=\dfrac{2010\times 2.53}{2010+1374.75}[/tex]

v' = 1.5 m/s

So, the speed of the car after the loading is completed is 1.5 m/s. Hence, this is the required solution.

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