Math help!!!!!!!!!!!!!
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Answer:
Option D: 2
Step-by-step explanation:
Given that:
4x + 2y = 6 ........... eq1
x-y = ....................... eq2
Using eq2:
x = 3 + y
Now put value of x in eq1
4(3 + y) + 2y = 6
By simplifying
12 + 4y + 2y = 6
12 + 6y =6
6y = 6 -12
6y = -6
Dividing both sides by 6 we get
y = -1
Now put value of y in eq2
x - (-1) = 3
x + 1 = 3
x = 3 - 1
x = 2
I hope it will help you!