Answer:
Initial velocity of the jaguar: 49 [tex]\frac{m}{s^2}[/tex] (answer d)
Explanation:
Considering that this uniformly accelerated problem (with negative acceleration since the jaguar was reducing its velocity to full stop), does not include the time the jaguar was skidding , we can use the kinematic equation that doesn't include time, but relates velocities (initial and final) with the acceleration ([tex]a[/tex]), and the distance "D" covered during the accelerated motion:
[tex]v_f^2-v_i^2=2\,a\,D[/tex]
For our problem, the initial velocity ([tex]v_i[/tex] is our unknown, the final velocity is zero ([tex]v_f = 0[/tex] - since the jaguar stops in the process), the negative acceleration is given as [tex]a=-4\,\frac{m}{s^2}[/tex], and the distance D of the skid marks is said to be 300 m in length. Therefore:
[tex]v_f^2-v_i^2=2\,a\,D\\0-v_i^2=2\,(-4)\,(300)\\v_1^2=2400\\v_1=\sqrt{2400} \\v_1=48.99\,\frac{m}{s^2}[/tex]
Which we can round to 49 [tex]\frac{m}{s^2}[/tex]
