3.) If Lebron James has a vertical leap of +1.35 m. then what is his takeoff speed7 For this
problem, the value of a, = -9.8 m/s2
a.) 5.17 m/s2
b.) 6.9 m/s
c.) 4.3 s
d.) Neither of these choices

Respuesta :

D, I hoped that helped you

The answer is 5.14 m/s is the answer. None of the options were correct.

Option: d

Explanation:

This is a question of kinematics. In the given question, acceleration [tex]a=-9.8 \mathrm{m} / \mathrm{s}^{2}[/tex]

Vertical loop of James is s = 1.35 m  

Final velocity of James is v = 0  

We are required to find the take-off speed of James i.e., using the second equation of motion,  

v² = u² + 2as

[tex]0-u^{2}=2 \times(-9.8) \times 1.35[/tex]

[tex]-\mathrm{u}^{2}=-19.6 \times 1.35[/tex]

[tex]\mathrm{u}^{2}=26.46[/tex]

u = 5.14 m/s (approx)  

So, the answer is none of the choices.