Respuesta :
The answer is 5.14 m/s is the answer. None of the options were correct.
Option: d
Explanation:
This is a question of kinematics. In the given question, acceleration [tex]a=-9.8 \mathrm{m} / \mathrm{s}^{2}[/tex]
Vertical loop of James is s = 1.35 m
Final velocity of James is v = 0
We are required to find the take-off speed of James i.e., using the second equation of motion,
v² = u² + 2as
[tex]0-u^{2}=2 \times(-9.8) \times 1.35[/tex]
[tex]-\mathrm{u}^{2}=-19.6 \times 1.35[/tex]
[tex]\mathrm{u}^{2}=26.46[/tex]
u = 5.14 m/s (approx)
So, the answer is none of the choices.