Answer:
The momentum of block B = -8 Kg m/s
Explanation:
Given,
The initial momentum of block A, MU = 15 Kg m/s
The initial momentum of block B, mu = -35 Kg m/s
The final momentum of block A, MV = -12 Kg m/s
The final momentum of block B, mv = ?
Consider the block B is initially at rest.
According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.
MU + mu = MV + mv
15 + (-35) = (-12) + mv
mv = -20 + 12
= -8 Kg m/s
Hence, the momentum of the block B after impact is, mv = -8 Kg m/s
