Answer:
in the sequence where [tex]a_n = 5a_{(n-1)} , a_4 = 125[/tex]
Step-by-step explanation:
Here, given [tex]a_1 = 1, a_n = 5a_{(n-1)}[/tex]
Now, the given n = 4
So, now here:
[tex]a_2 = 5a_{(2-1)} = 5a_1 =5\times 1 = 5[/tex]
⇒Second term of the sequence = 5
Now, [tex]a_3 = 5a_{(3-1)} = 5a_2 =5\times 5 = 25[/tex]
⇒Third term of the sequence = 25
Also, Now, [tex]a_4 = 5a_{(4-1)} = 5a_3 =5\times 25 = 125[/tex]
⇒Forth term of the sequence = 125
Hence, in the sequence where [tex]a_n = 5a_{(n-1)} , a_4 = 125[/tex]
