Help please find jkl, kjn, klj, klm.
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An outside angle is equal to the two opposite inside angles:
9x -8 = (7x-32) + (5x-27)
Simplify:
9x -8 = 12x - 59
Add 59 to both sides:
9x + 51 = 12x
Subtract 9x from both sides:
3x = 51
Divide both sides by 3:
X = 51/3
x = 17
Now you have X, solve all 3 angles:
7x-32 = 7(17) -32 = 119-32 = 87
5x-27 = 5(17) - 27 = 85-27 = 58
9x -8 = 9(17) -8 = 153-8 = 145