Answer:
The equation of line AB with points (3,3) and (-3,5) is given as
: x + 3y = 12
Step-by-step explanation:
Here, the given points are A (3, 3) and B (-3,5).
Now, slope of any line is given as :
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
or, [tex]m = \frac{5-3}{-3 - 3} = \frac{2}{-6} = -\frac{1}{3}[/tex]
Hence, the slope of the line AB is (-1/3)
Now , A POINT SLOPE FORM of an equation is
(y - y0) = m (x - x0) ; (x0, y0) is any arbitrary point on line.
So, for the point (3,3) the equation of the line is
y - 3[tex]y-3 = -\frac{1}{3} (x-3) \implies 3y - 9 = 3 -x[/tex]
Hence, the equation of line AB with points (3,3) and (-3,5) is given as:
x + 3y = 12
