The equation of line passing through the points (3,3) and (-3,5) is:
x+3y=12
Step-by-step explanation:
Given points are:
(x1, y1) = (3,3)
(x2, y2) = (-3, 5)
The general form of slope-intercept form is:
[tex]y=mx+b[/tex]
We have to find slope first
[tex]m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{5-3}{-3-3}\\=\frac{2}{-6}\\=-\frac{1}{3}[/tex]
Putting the value of m in general form
[tex]y=-\frac{1}{3}x+b[/tex]
To find the value of b, putting (3,3) in equation
[tex]3=-\frac{1}{3}(3)+b\\3=-1+b\\b=4[/tex]
Putting the values of m and b in general form
[tex]y=-\frac{1}{3}x+4[/tex]
Multiplying both sides by 3
[tex]3y=-x+12\\x+3y=12[/tex]
The equation of line passing through the points (3,3) and (-3,5) is:
x+3y=12
Keywords: Equation of line, Standard form
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