Answer:
The relation between m and n is , m = n
Step-by-step explanation:
Given as :
The average for n class = 0.82 = 82%
The average for m class = 0.78 = 78%
The average for ( m + n ) class = 80%
So , [tex]\frac{x_1 +x_2+x_3+x_4+ ....... + x_n}{n}[/tex] = 82%
And [tex]\frac{x_1 +x_2+x_3+x_4+ ....... + x_m}{m}[/tex] = 78%
And , [tex]\frac{(x_1+x_2+x_3+x_4+ ......+x_n ) + (x_1+x_2+x_+x_4+.....+x_m)}{m+n}[/tex] = 80%
So , 0.82×n + 0.78×m = 0.80× (m+n)
Or, 0.82×n - 0.80×n = 0.80×m - 0.78×m
Or, 0.02×n = 0.02×m
Or, [tex]\frac{m}{n}[/tex] = [tex]\frac{0.02}{0.02}[/tex]
∴ [tex]\frac{m}{n}[/tex] = 1
I.e m = n
Hence The relation between m and n is , m = n Answer
