The range is: {3,-5}
Step-by-step explanation:
Given
[tex]h(x)=x^2 + 2x - 5[/tex]
We will get the range by putting the values given in domain in the function
Putting x=-4
[tex]h(-4)=(-4)^2 + 2(-4) - 5\\=16-8-5\\=16-13\\=3[/tex]
Putting x=-2
[tex]h(-2)=(-2)^2 +2(-2) - 5\\=4-4-5\\=0-5\\=-5[/tex]
Putting x=0
[tex]h(0)=(0)^2 + 2(0) - 5\\=0+0-5\\=-5\\[/tex]
Putting x=2
[tex]h(2)=(2)^2 + 2(2) - 5\\=4+4-5\\=8-5\\=3[/tex]
The range is: {3,-5}
Keywords: Functions, Range
Learn more about range at:
- brainly.com/question/5528742
- brainly.com/question/5533462
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