Respuesta :

nkirotedoreen46

Answer:

2.047 × 10^24 atoms

Explanation:

  • We need to know that 1 mole of an element contains atoms equivalent to the Avogadro's constant.
  • The Avogadro's constant is 6.022 × 10^23.
  • Therefore, 1 mole of Fe contains 6.022 × 10^23 atoms.

In this case we are given 3.4 moles of Iron.

we are required to find the number of atoms in 3.4 moles.

Therefore, since 1 mole of Fe contains 6.022 × 10^23 atoms.

Then, 3.4 mole will contain;

= 3.4 moles × 6.022 × 10^23 atoms/mole

= 2.047 × 10^24 atoms

Thus, 3.4 moles of Iron contains 2.047 × 10^24 atoms

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