He has 14 dimes and 15 quarters in his pocket
Step-by-step explanation:
A man has 29 coins in his pocket, where
We need to find how many dimes and quarters in his pocket
Assume that there are d dimes and q quarter in his pocket
∵ There are d dimes in the pocket
∵ There are q quarter in the pocket
∵ There are 29 coins in the pocket
∴ d + q = 29 ⇒ (1)
∵ 1 dime = 10 cents
∵ 1 quarter = 25 cents
∵ The total value of the coins is 515 cents
∴ 10 d + 25 q = 515 ⇒ (2)
Now we have system of equations we can solve it to find d and q
- Multiply equation (1) by -10 to eliminate d
∵ (-10) d + (-10) q = (-10)(29)
∴ -10 d - 10 q = -290 ⇒ (3)
Add equations (2) and (3)
∴ 15 q = 225
- Divide both sides by 15
∴ q = 15
∴ There are 15 quarters in the pocket
Substitute the value of q in equation (1)
∵ d + 15 = 29
- Subtract 15 from both sides
∴ d = 14
∴ There are 14 dimes in the pocket
He has 14 dimes and 15 quarters in his pocket
Learn more:
You can learn more about solving linear equations in brainly.com/question/13168205
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