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The drag force for falling objects due to air friction depends on the velocity of the object and is given by the equation Drag = b where b is a constant that depends on the fluid through which the object moves and the radius of the object.
(a)Find the terminal speed of an object of mass 59.0 kg for which b = 11.0 kg/s.
(b) Will the terminal speed be different if the object's initial speed is different?

Respuesta :

cmocampo

Answer:

a. Terminal speed for this object is 52.62 m/s, approximately.

b. No, the terminal velocity WILL NOT change if the object's initial speed changes.

Explanation:

a. The object will reach terminal velocity when the drag force equals the weight, i.e.

[tex]Drag=w\\v_{ter}b=mg\\v_{ter}=\frac{mg}{b}=\frac{59kg\times 9.81 m/s^2}{11 kg/s}\approx 52.62 m/s[/tex]

b. The terminal velocity will remain. If the object is dropped from rest the velocity will increase until the drag force equals the weight, as seen previously; if the object is thrown with a velocity greater than the terminal one, it will slow down until it reaches this last one, since the drag is way too big.