Respuesta :
Answer:
Explanation:
Rachel and Sarah are standing on horizontal ground . Let T₁ be the tension between Rachel and Sarah and Sarah is in between you.
Force = mass x acceleration
Apply this equation on Rachel
T₁ = 23 x 2 = 46 N
Let T₂ be tension between Sarah and me and it is inclined at 60°
Force = mass x acceleration
Apply this equation on Sarah
T₂ cos 60 - T₁ = 23 X 2 = 46
T₂ cos 60 - 46 =46
T₂ cos 60 = 92
T₂ = 92 / .5
= 184 N
Answer:
46N and 184N
Explanation:
parameters given
angle of inclination of the force on sarah = 60⁰
mass of sarah = mass of rachel = 23kg
acceleration (equal for all the bodies) = 2.0m/s²
F is the force exerted on Sarah's arm
T is the tension between Sarah and Rachel
let the forces acting and the body diagram be represented as shown in the diagram below
the tension T exacted on rachel is given by
T = ma
hence
T = 23 × 2 = 46N
this is the force sarah exerts on Rachel
Now the Force exerted on Sarah's arm is given by
[tex]Fcos60^{0} - T = ma[/tex]
where Fcos 60⁰ is the component of the force exerted on sarah's arm in the horizontal direction
now, T = 46N, mass of sarah, m = 23 kg and acceleration, a = 2m/s²
making F the subject of formula
[tex]F = \frac{ma + T}{cos 60^{0} }[/tex]
[tex]F = \frac{(23 * 2) + 46 }{cos 60^{0} }[/tex]
F = 184N
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